What formula does this calculator use?
Multiply VA by power factor and divide by 1000.
Volt-amperes to kilowatts
Calculate real power in kilowatts from volt-amperes and power factor.
Interactive calculator
Result
1.840 kW
kW = VA × PF ÷ 1000
Live circuit diagram
Values update as you use the calculator.
Input
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Circuit setting
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Calculated output
Enter values to see the live result
Quick answers
Get concise answers to the most common va to kw calculator questions before reviewing the formulas, examples, and detailed guidance below.
Multiply VA by power factor and divide by 1000.
5000 VA at PF 0.9 equals 4.5 kW.
Volt-amperes measure apparent AC power, the product of RMS voltage and current before power-factor conversion.
Formula
Choose the formula that matches the electrical system and known values.
kW = VA × PF ÷ 1000
Convert watts to kilowatts.
kW = VA ÷ 1000
Applies at PF 1.
VA = kW × 1000 ÷ PF
Find apparent power demand.
How to use
Check every unit and use measured or nameplate values where possible.
Worked examples
Examples make the formula and its assumptions easier to verify.
1,000 VA at PF 1
1 kW
2,300 VA at PF 0.8
1.84 kW
5,000 VA at PF 0.9
4.5 kW
10,000 VA at PF 0.85
8.5 kW
25,000 VA at PF 0.8
20 kW
50,000 VA at PF 0.95
47.5 kW
Accuracy
The result is only as reliable as the selected formula and input data.
Conversion library
Continue from the VA to kW Calculator to a dedicated conversion tool for watts, amps, volts, kW, kVA, energy, batteries, or circuit calculations. Each linked page includes its own formula, examples, and guidance.
FAQ
Direct answers to common calculation questions.
Multiply VA by power factor and divide by 1000.
5000 VA at PF 0.9 equals 4.5 kW.
Volt-amperes measure apparent AC power, the product of RMS voltage and current before power-factor conversion.
Yes. Without PF, VA cannot accurately convert to kW.
Only at power factor 1; otherwise watts are lower than VA.
Yes. Enter positive decimal values in the displayed units.
Use it for estimates, then verify duty, surge, derating, manufacturer data, and applicable codes.
Efficiency is separate from power factor and must be evaluated when comparing input and output power.
Voltage variation, harmonics, load changes, imbalance, and meter accuracy can affect field values.
Yes. Use the copy button below the result.
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